Question: 
Write a python function to find the kth element in an array containing odd elements first and then even elements.


Model's Code:
def get_Number(n, k):
    odd_count = (n + 1) // 2
    if k <= odd_count:
        return 2 * k - 1
    else:
        return 2 * (k - odd_count)



Sample Correct Code:
def get_Number(n, k): 
    arr = [0] * n; 
    i = 0; 
    odd = 1; 
    while (odd <= n):   
        arr[i] = odd; 
        i += 1; 
        odd += 2;
    even = 2; 
    while (even <= n): 
        arr[i] = even; 
        i += 1;
        even += 2; 
    return arr[k - 1]; 


Asserts:
assert get_Number(8,5) == 2
assert get_Number(7,2) == 3
assert get_Number(5,2) == 3


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 844 of 974: 648/844 (76.77725118483413%): success