Question: 
Write a python function to find the cube sum of first n odd natural numbers.


Model's Code:
def cube_Sum(n):
    return sum((2*i + 1) ** 3 for i in range(n))



Sample Correct Code:
def cube_Sum(n): 
    sum = 0   
    for i in range(0,n) : 
        sum += (2*i+1)*(2*i+1)*(2*i+1) 
    return sum


Asserts:
assert cube_Sum(2) == 28
assert cube_Sum(3) == 153
assert cube_Sum(4) == 496


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 837 of 974: 643/837 (76.82198327359617%): success