Question: 
Write a python function to check whether the count of divisors is even or odd.


Model's Code:
def count_Divisors(n):
    count = 0
    for i in range(1, int(n**0.5) + 1):
        if n % i == 0:
            count += 1
            if i != n // i:
                count += 1
    return "Even" if count % 2 == 0 else "Odd"



Sample Correct Code:
import math 
def count_Divisors(n) : 
    count = 0
    for i in range(1, (int)(math.sqrt(n)) + 2) : 
        if (n % i == 0) : 
            if( n // i == i) : 
                count = count + 1
            else : 
                count = count + 2
    if (count % 2 == 0) : 
        return ("Even") 
    else : 
        return ("Odd") 


Asserts:
assert count_Divisors(10) == "Even"
assert count_Divisors(100) == "Odd"
assert count_Divisors(125) == "Even"


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 781 of 974: 590/781 (75.54417413572342%): success