Question: 
Write a python function to count the pairs with xor as an odd number.


Model's Code:
def find_Odd_Pair(arr, n):
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            if (arr[i] ^ arr[j]) % 2 == 1:
                count += 1
    return count



Sample Correct Code:
def find_Odd_Pair(A,N) : 
    oddPair = 0
    for i in range(0,N) :  
        for j in range(i+1,N) :  
            if ((A[i] ^ A[j]) % 2 != 0):  
                oddPair+=1  
    return oddPair  


Asserts:
assert find_Odd_Pair([5,4,7,2,1],5) == 6
assert find_Odd_Pair([7,2,8,1,0,5,11],7) == 12
assert find_Odd_Pair([1,2,3],3) == 2


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 556 of 974: 411/556 (73.92086330935251%): success