Question: 
Write a function to find if the given number is abundant or not.


Model's Code:
def check_abundant(n):
    if n < 1:
        return False
    divisors_sum = sum(i for i in range(1, n) if n % i == 0)
    return divisors_sum > n



Sample Correct Code:
import math 
def get_sum(n): 
	sum = 0
	i = 1
	while i <= (math.sqrt(n)): 
		if n%i == 0: 
			if n/i == i : 
				sum = sum + i 
			else: 
				sum = sum + i 
				sum = sum + (n / i ) 
		i = i + 1
	sum = sum - n 
	return sum
def check_abundant(n): 
	if (get_sum(n) > n): 
		return True
	else: 
		return False


Asserts:
assert check_abundant(12) == True
assert check_abundant(15) == False
assert check_abundant(18) == True


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 541 of 974: 399/541 (73.75231053604436%): success