Question: 
Write a function to find the demlo number for the given number.


Model's Code:
def find_demlo(n):
    count = {}
    for digit in n:
        count[digit] = count.get(digit, 0) + 1
    result = []
    for i in range(1, 10):
        if str(i) in count:
            result.append(str(i) * count[str(i)])
    increasing = ''.join(result)
    decreasing = increasing[::-1]
    return increasing + decreasing[1:]



Sample Correct Code:
def find_demlo(s): 
	l = len(s) 
	res = "" 
	for i in range(1,l+1): 
		res = res + str(i) 
	for i in range(l-1,0,-1): 
		res = res + str(i) 
	return res 	


Asserts:
assert find_demlo("111111") == '12345654321'
assert find_demlo("1111") == '1234321'
assert find_demlo("13333122222") == '123456789101110987654321'


Tests:
Test 1 of 3: FAIL: AssertionError()

Test 321 of 974: 230/321 (71.65109034267913%): failed