Question: 
Write a python function to count the pairs with xor as an even number.


Model's Code:
def find_even_Pair(arr, n):
    count = 0
    for i in range(n):
        for j in range(i + 1, n):
            if (arr[i] ^ arr[j]) % 2 == 0:
                count += 1
    return count



Sample Correct Code:
def find_even_Pair(A,N): 
    evenPair = 0
    for i in range(0,N): 
        for j in range(i+1,N): 
            if ((A[i] ^ A[j]) % 2 == 0): 
                evenPair+=1
    return evenPair; 


Asserts:
assert find_even_Pair([5,4,7,2,1],5) == 4
assert find_even_Pair([7,2,8,1,0,5,11],7) == 9
assert find_even_Pair([1,2,3],3) == 1


Tests:
Test 1 of 3: PASS
Test 2 of 3: PASS
Test 3 of 3: PASS

Test 166 of 974: 121/166 (72.89156626506023%): success